The correct answer is **B) $15.0$**.\n\nWe need to systematically fill the table using the given conditions and the arithmetic consistency of rows and columns.\nAll values are in hundreds of licenses.\n\nLet's denote the missing values as in the table:\n\n$$\\begin{array}{|c|c|c|c|c|c|}\n\\hline\n\\textbf{Package} & \\textbf{North} & \\textbf{South} & \\textbf{East} & \\textbf{West} & \\textbf{Total} \\\\\n\\hline\n\\textbf{Alpha} & 4.0 & A_S & A_E & 5.0 & A_T \\\\\n\\textbf{Beta} & B_N & 5.0 & B_E & 6.0 & B_T \\\\\n\\textbf{Gamma} & G_N & G_S & G_E & G_W & G_T \\\\\n\\hline\n\\textbf{Total} & N_T & S_T & E_T & W_T & \\text{Grand Total} \\\\\n\\hline\n\\end{array}$$\n\n**Step-by-step Filling:**\n\n1. **From Condition 1:** Sales of Alpha in the South region ($A_S$) were $3.0$.\n So, $A_S = 3.0$.\n\n2. **From Condition 2:** Sales of Beta in the North region ($B_N$) were $2.0$.\n So, $B_N = 2.0$.\n\n3. **From Condition 3:** Sales of Gamma in the North region ($G_N$) were $3.0$.\n So, $G_N = 3.0$.\n\n4. **From Condition 4:** The total sales of Alpha packages ($A_T$) were $18.0$.\n Using the Alpha row: $A_N + A_S + A_E + A_W = A_T$\n $4.0 + 3.0 + A_E + 5.0 = 18.0$\n $12.0 + A_E = 18.0$\n $A_E = 18.0 - 12.0 = 6.0$.\n\n5. **From Condition 6:** The sales of Alpha in the East region ($A_E$) were $2.0$ more than the sales of Beta in the East region ($B_E$).\n $A_E = B_E + 2.0$\n $6.0 = B_E + 2.0$\n $B_E = 6.0 - 2.0 = 4.0$.\n\n6. **From Condition 8:** The total sales of Beta packages ($B_T$) were $17.0$.\n Let's check this for consistency with the values we have for Beta:\n $B_N + B_S + B_E + B_W = B_T$\n $2.0 + 5.0 + 4.0 + 6.0 = 17.0$\n $17.0 = 17.0$. This is consistent.\n\n7. **From Condition 5:** Total sales in the East region ($E_T$) were $15.0$.\n Using the East column: $A_E + B_E + G_E = E_T$\n $6.0 + 4.0 + G_E = 15.0$\n $10.0 + G_E = 15.0$\n $G_E = 15.0 - 10.0 = 5.0$.\n\n8. **From Condition 9:** Sales of Gamma in the South region ($G_S$) were $40\\%$ of the sales of Beta in the South region ($B_S$).\n $G_S = 0.40 \\times B_S$\n $G_S = 0.40 \\times 5.0 = 2.0$.\n\n9. **From Condition 10:** Total sales in the West region ($W_T$) were $16.0$.\n Using the West column: $A_W + B_W + G_W = W_T$\n $5.0 + 6.0 + G_W = 16.0$\n $11.0 + G_W = 16.0$\n $G_W = 16.0 - 11.0 = 5.0$.\n\nAll necessary values for the Gamma row are now determined. We need to find $G_T$.\n\n10. **Calculate Total sales of Gamma packages ($G_T$):**\n $G_T = G_N + G_S + G_E + G_W$\n $G_T = 3.0 + 2.0 + 5.0 + 5.0$\n $G_T = 15.0$.\n\n**Final Table (for completeness, not required for the specific question):**\n\n$$\\begin{array}{|c|c|c|c|c|c|}\n\\hline\n\\textbf{Package} & \\textbf{North} & \\textbf{South} & \\textbf{East} & \\textbf{West} & \\textbf{Total} \\\\\n\\hline\n\\textbf{Alpha} & 4.0 & 3.0 & 6.0 & 5.0 & 18.0 \\\\\n\\textbf{Beta} & 2.0 & 5.0 & 4.0 & 6.0 & 17.0 \\\\\n\\textbf{Gamma} & 3.0 & 2.0 & 5.0 & 5.0 & 15.0 \\\\\n\\hline\n\\textbf{Total} & 9.0 & 10.0 & 15.0 & 16.0 & 50.0 \\\\\n\\hline\n\\end{array}$$\n\nAll column totals and the Grand Total are consistent (e.g., $N_T = 4+2+3=9$, $S_T = 3+5+2=10$, $E_T=6+4+5=15$, $W_T=5+6+5=16$. Grand Total $= 18+17+15 = 50$, and $9+10+15+16 = 50$).\n\nThe total sales of Gamma packages ($G_T$) are $15.0$ (in hundreds).\n\nThe final answer is $\\boxed{\\text{15.0}}$