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A right circular cone has its height equal to the diameter of its base. A right circular cylinder has the same base radius as the cone. If the volume of the cylinder is four times the volume of the cone, what is the ratio of the height of the cylinder to the height of the cone? A) $3:2$ B) $2:1$ C) $4:3$ D) $1:1$
The correct answer is C. Let $r_c$ and $h_c$ be the radius and height of the cone, respectively. Let $r_{cy}$ and $h_{cy}$ be the radius and height of the cylinder, respectively. From the problem statement, we are given the following conditions: 1. The height of the cone is equal to the diameter of its base. This implies $h_c = 2r_c$. 2. The cylinder has the same base radius as the cone. This implies $r_{cy} = r_c$. Let us denote this common radius as $r$. Therefore, $r_c = r$ and $r_{cy} = r$. From condition (1), substituting $r_c = r$, we get $h_c = 2r$. 3. The volume of the cylinder is four times the volume of the cone. This can be written as $V_{cy} = 4 \times V_c$. Now, let's write down the standard formulae for the volumes of a right circular cone and a right circular cylinder: Volume of a cone, $V_c = \frac{1}{3} \pi r_c^2 h_c$. Volume of a cylinder, $V_{cy} = \pi r_{cy}^2 h_{cy}$. Substitute the given conditions into these volume formulae: For the cone: Using $r_c = r$ and $h_c = 2r$, we get: $V_c = \frac{1}{3} \pi (r)^2 (2r)$ $V_c = \frac{2}{3} \pi r^3$ For the cylinder: Using $r_{cy} = r$, we get: $V_{cy} = \pi (r)^2 h_{cy}$ $V_{cy} = \pi r^2 h_{cy}$ Now, we use the relationship between their volumes as stated in condition (3): $V_{cy} = 4 \times V_c$ Substitute the expressions for $V_{cy}$ and $V_c$: $\pi r^2 h_{cy} = 4 \times \left( \frac{2}{3} \pi r^3 \right)$ $\pi r^2 h_{cy} = \frac{8}{3} \pi r^3$ To find $h_{cy}$, we can divide both sides of the equation by $\pi r^2$ (since $r$ is a radius, $r \neq 0$): $h_{cy} = \frac{8}{3} r$ The problem asks for the ratio of the height of the cylinder to the height of the cone, which is $\frac{h_{cy}}{h_c}$. We have $h_{cy} = \frac{8}{3} r$ and we found earlier that $h_c = 2r$. Now, compute the ratio: $\frac{h_{cy}}{h_c} = \frac{\frac{8}{3} r}{2r}$ Cancel out $r$ from the numerator and denominator: $\frac{h_{cy}}{h_c} = \frac{8}{3 \times 2}$ $\frac{h_{cy}}{h_c} = \frac{8}{6}$ $\frac{h_{cy}}{h_c} = \frac{4}{3}$ Thus, the ratio of the height of the cylinder to the height of the cone is $4:3$.
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