The correct option is (B) Detailed Breakdown & Solution To find the maximum value of the function $f(x) = \min \{10 + 4x - x^2, 2x + 2\}$, we need to understand how the two component functions behave and where they intersect. Let the two functions be: $g(x) = 10 + 4x - x^2$ (a downward-opening parabola) $h(x) = 2x + 2$ (a straight line with a positive slope) Step 1: Find the points of intersection To find where $g(x)$ and $h(x)$ meet, we equate them: $$10 + 4x - x^2 = 2x + 2$$ $$x^2 - 2x - 8 = 0$$ $$(x - 4)(x + 2) = 0$$ This gives us two intersection points: $x = 4$ and $x = -2$. At $x = 4$, the height is $h(4) = 2(4) + 2 = 10$. At $x = -2$, the height is $h(-2) = 2(-2) + 2 = -2$. Step 2: Analyze the behavior of the minimum function The function $f(x)$ takes the smaller value of the two functions at any given point $x$. Let's divide the real number line into three regions based on our intersection points: 1. Region I: $x < -2$ Let's test $x = -3$: $g(-3) = 10 + 4(-3) - (-3)^2 = 10 - 12 - 9 = -11$ $h(-3) = 2(-3) + 2 = -4$ Since -11 is smaller than -4, $f(x)$ follows the parabola $g(x)$. Since the vertex of this parabola is at $x = 2$, this branch is strictly increasing up to $x = -2$, reaching a value of -2. 2. Region II: $-2 \le x \le 4$ Let's test $x = 2$ (the vertex of the parabola): $g(2) = 10 + 4(2) - 2^2 = 14$ $h(2) = 2(2) + 2 = 6$ Since 6 is smaller than 14, $f(x)$ follows the straight line $h(x) = 2x + 2$. This line strictly increases from -2 (at $x = -2$) to 10 (at $x = 4$). 3. Region III: $x > 4$ Let's test $x = 5$: $g(5) = 10 + 4(5) - 5^2 = 5$ $h(5) = 2(5) + 2 = 12$ Since 5 is smaller than 12, $f(x)$ follows the parabola $g(x)$. Since the vertex is at $x = 2$, for $x > 4$, the parabola is strictly decreasing. Its values will always be less than 10. Conclusion Tracing the function from left to right: It increases on the parabolic curve up to the point $(-2, -2)$. It then increases linearly along the line $y = 2x + 2$ from $(-2, -2)$ up to $(4, 10)$. After $(4, 10)$, it falls along the parabolic curve toward $-\infty$. Therefore, the absolute highest peak of the function occurs at $x = 4$, giving a maximum value of 10.